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The Correlation Between Natural Science And The Humanities At School

Table 1:

Given:ω (H2SO4) = 20%m (oleum) = 50 kgω (SO3) = 10% Solution:m (SO3) = 50 кг · 0,1 = 5 kgm (H2SO4) = 50 - 5 = 45 kg in oleumν (SO3) = 5 kg / 80 kg/kmol = 0,0625 kmolH2SO4 · хSO3 → H2SO40,0625kmol 0,0625 кмоль SO3 + Н2О = H2SO41 kmol 1 kmol m (H2SO4) = 98 kg/kmol · 0,0625 kmol = 6,125 kgm (H2SO4) = 45 kg + 6,125 kg = 51,125 kg commonm (solut) = 51,125 kg / 0,2 = 255,625 kgОтвет: m (solut) = 255,625 kg
m (solut) - ?
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